I’ve put my cards on the table (well on my blog), Mankind show me yours?

Qubit

Looking (so to speak) at a thought experiment is mostly done in what we regarded as the past, just like we have experienced it as a memory, but instead of experiencing it, we have created it in the way that we would have experienced it.

If the future is undecided then all possible outcomes have to be taking into consideration, if you have the knowledge of it occurrence in advance, then that question can be answered, without experiencing it in the past.

The 2nd law of thermodynamics can be over come by using tricks! But trick are exactly what they appear to be.

“I never think of the future - it comes soon enough.” You don’t come up with that sentence and E=MC2 without telling everybody what really E=MC2 is, unless your lying. Einstein thought of the future more than most!

“If A is a success in life, then A equals x plus y plus z. Work is x; y is play; and z is keeping your mouth shut.”

Who am I to tell you what Z is?

Qubit

Laplace’s demon can be an effective Maxwell’s demon and lower the entropy of a system. Ordinary Maxwell’s demons always fail to be effective, because with incomplete information about the system they must make measurements. They must store and process information, but with finite memories they can’t ecape having to reset their memory which is an irreversible process leading to entropy increase.

“Qubit, if the law of entropy holds true,how does one explain that the universe appears ordered or that complex entities such as ourselves even exist?”

Brett
By knowledge of something in advance of its occurrence; Precognition.
Do smart people really tell the truth?

That all I am saying at the moment, am full of cold!

This is an impossible thought experiment, because thinking about the box, has the same effect on the box as gravity; its an external force that penetrates the closed system of the box and the outside of the box, it makes the cannon ball heavy and light mass less, and the surface on the outside frictionless. How is it classed as a closed system?

I’ve heard another one about entropy and an ice cube melting on the table. How does the ice cube get there in the first place? Closed System? no way!

Creating Mass from Energy, cannot surely be equivilent to Creating Energy from Mass, there has to be subtle differences?

A constraining box?..that has no transitional space available (except the length of the barrel of the cannon)..what would the outcome be?

Would an explosion occur? this of course nullifies the closed system concept.

The shortness of the available transitional space, dictates the outcome, think of a larger available space (a box that has a large distance from side to side)..then no evidence of the exchange of momentum would occur, not for a long time at least, for if the cannonball fails to interact with a boxside, then the result would be of a closed system box, travelling across the ice in ONE certain direction?

The term left-handedness come to mind?

You start with the usual equations of special relativity, you put c = 1 everywhere. Mass is the same as energy, so there would be no point in introducing a quantity M if you are not going to use it (just like Galileo never wrote the equation t’ = t)
The energy and momentum are given by

E(v) = gamma(v) E(0)

P(v) = v E(v) = gamma(v) v E(0)

Here v is the dimensionless velocity (time and distances are measured in the same units), gamma(v) = 1/sqrt[1-v^2] and E(0) is the rest energy.

Now consider phenomena at extremely low velocities. Just like if you want to see a plant growing you can take pictures every day and make a video such that 1 second corresponds to one day, in this case we should rescale time relative to space and formulate things in terms of the new variables. We define:

t_{slow} = t/c

where c is a (dimensionless) rescaling parameter. If we make c larger and larger, then for t_{slow} to stay of order unity, t must also become larger and larger. So, the large c limit is appropriate for studying phenomena that move very slowly.

If we define:

v_{slow} = dx/dt_{slow},

then:

v_{slow} = c v

We now consider what happens for c–> infinity while v_{slow} is kept constant, i.e. we run the video faster and faster but keep concentrating on things that appear to move at the same rate on the monitor.

The kinetic energy can be written as:

E_{kin}= E(v)-E(0)=

E(v_{slow}/c) - E(0) =

1/2 E(0) v_{slow}^2/c^2 + 3/8 E(0) v_{slow}^4/c^4 +…

And the momentum is:

P = gamma(v_{slow}/c) v_{slow}/c E(0) =

E(0) v_{slow}/c + …

Now, as we make clarger and larger, the things we see on the monitor may have E(0)’s that change too, so we should write:

E(0) = E(0,c)

Also, the energy and momentum should be rescaled to make sure we end up with equations that have finite coefficients in the limit c –> infinity. In this limit the equaton for the energy is:

E_{kin} = 1/2 E(0,c) v_{slow}^2/c^2

If we put:

E_{slow} = E c^p

where p is some exponent we’ll determine later, then:

E_{slow,kin} = 1/2 E_{slow}(0,c) v_{slow}^2/c^2

We have now expressed everything in “slow” variables and should now demand that in the c–> infinity limit, the equation does not become degenerate. This means that we must demand that

E_{slow}(0,c) = m c^2

for some constant m.

The momentum is given by:

P = E(0,c) v_{slow}/c =

mc^(-p+1) v_{slow}

And we see that we have to put:

P = P_{slow} c^(-p+1)

To find the exponent p, you can express E in terms of P, rewrite it in terms of the slow variables and demand that the equation does not become degenerate in the c –> infinity limit. You find that p has to be put equal to zero.

But still,it can’t explain why E=mc^2 ,maybe it can be write E=(mc^2)/2.or other form for caculates the energy of motion.

Hi holdsky28. Are you referring to the argument I gave, or to comment #51?